emitter junction การใช้

• At high overdrive the base-emitter junction gets reversed.
• In parallel with the collector emitter junction of the transistor.
• The voltage across R 2 forward biases the emitter junction.
• The input resistance is high again since the base-emitter junction is cutoff.
• According to the rectified when it flows through the base / emitter junction of a bipolar transistor.
• The negative supply V EE is used to forward-bias the emitter junction through R E.
• When the transistor conducts, there will be about 0.6 V across its base emitter junction.
• During the negative half-cycle, the base-emitter junction is reverse biased and hence no current flows.
• This reduction in resistance means that the emitter junction is more forward biased, and so even more current is injected.
• During State 1, Q2 base-emitter junction is reverse-biased and capacitor C1 is " unhooked " from ground.
• During State 2, Q2 base-emitter junction is forward-biased and capacitor C1 is " hooked " to ground.
• The emitter junctions of these amplifier stages are fed by the collectors of a third differential pair ( Q2 / Q6 ).
• When all the inputs are held at high voltage, the base emitter junctions of the multiple-emitter transistor are reverse-biased.
• As Q2 base-emitter junction is reverse-biased, it does not conduct, so all the current from R2 goes into C1.
• The base resistor R B is obligatory to prevent the impact of the input voltage through Q1 base-emitter junction on the emitter voltage.
• The input base resistor can be omitted since the emitter resistor limits the current when the input base-emitter junction is forward-biased.
• If one input voltage becomes zero, the corresponding base-emitter junction of the multiple-emitter transistor is in parallel with these two junctions.
• When compensated for temperature, the forward voltage drop of a transistor's base-emitter junction can provide a usably accurate logarithmic or exponential function.
• This resistor provides a low-impedance discharge path for the charge accumulated on the base-emitter junction, allowing a faster transistor turn-off.
• This current passes through the base-emitter junction of the output transistor, allowing it to conduct and pulling the output voltage low ( logical zero ).